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設三角形為ΔABC,O為其中一點,[ ]表示向量,∠A,B,C所對邊分別為a,b,c1.若a[OA]+b[OB]+c[OC]=0,則O為內心,角平分線的交點2.若[OA]+[OB]+[OC]=0,則0為重心,中線的交點3.若[OA]*[OB]=[OB]*[OC]=[OC]*[OA],則0為垂心,高…
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