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對於分佈函數有F(X)=A+Barctanx F(-∞)=A+B(-π/2)=0 F(+∞)=A+B(π/2)=1 A=1/2,B=1/π 即F(X)=1/2+arctanx/π F(1)-F(-1)=1/2+arctan(1)/π-(1/2+arctan(-1)/π)=1/2 如有意見,歡迎討論,共同學習;如有幫助,
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