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求以抛物線y=-2x的二次方+1與直線y=-7的交點: -2x²;+1=-7解得x=±2 ∴兩交點為A(2,-7),B(-2,-7) 而抛物線y=-2x的二次方+1的頂點為C(0,1) ∴交點和頂點所構成的⊿ABC面積=4*8/2=16
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