What is the area of the triangle formed by the intersection and vertex of the parabola y = - 2x and the straight line y = - 7?

What is the area of the triangle formed by the intersection and vertex of the parabola y = - 2x and the straight line y = - 7?

Find the intersection point of parabola y = - 2x quadratic power + 1 and straight line y = - 7
-2X & sup2; + 1 = - 7 gives x = ± 2
The two intersection points are a (2, - 7), B (- 2, - 7)
The vertex of parabola y = - 2x + 1 is C (0,1)
The area of ⊿ ABC formed by intersection and vertex is 4 * 8 / 2 = 16