已知x=1/2a+1,y=1/2a+a,z=a-3,求x2+2xy+y2-2xz+z2-2yz 問題錯了已知x=1/2a+1,y=1/2a+2,z=a-3,求x2+2xy+y2-2xz+z2-2yz的值,答案是36

已知x=1/2a+1,y=1/2a+a,z=a-3,求x2+2xy+y2-2xz+z2-2yz 問題錯了已知x=1/2a+1,y=1/2a+2,z=a-3,求x2+2xy+y2-2xz+z2-2yz的值,答案是36

原式=(x+y)²;-2z(x+y)+z²;
=(x+y-z)²;
=(1/2a+1+1/2a+a-a+3)²;
=(a+4)²;
=a²;+8a+16