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從影像的角度去想該函數抛物線開口向上代入-b/2a求得對稱軸為x=2再代入,求得頂點座標是(2,-7)再求最大值和最小值當x=-1時y=2當x=6時y=9因為最低點是-7又x從-1到2的時候遞減x從2到6是新增所以得出-7≤y≤9 -7≤…
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