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因為圖像經過A(-1,0)、B(3,0), 所以可設函數為 y=a(x+1)(x-3) y=ax^2-2ax-3a =a(x^2-2x)-3a =a(x-1)^2-4a 因為函數最小值是-8,即 -4a=-8 a=2 所以 這個二次函數的解析式是y=2(x+1)(x-3)=2x^2-4x-6
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