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若函數y=(a-1)x^(b+1)+x^2+1是二次函數,試討論,a,b的取值範圍因為函數y=(a-1)x^(b+1)+x^2+1是二次函數所以x的指數b+1=0或b+1=1或b+1=2當b+1=0,即b=-1時,a-1為任意實數.即a為任意實數當b+1=1,即b=0時,a-1為任意實數…
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