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當x=3時,y最小值=-1 所以y=a(x-3)^2-1 有最小值,所以a>0 把(0,7)代入 7=a*(0-3)^2-1 a=8/9,符合a>0 所以y=(8/9)(x-3)^2-1 =(8/9)x^2-(16/3)x+7
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