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設解析式為y=ax²;+bx+c,由題意得 a-b+c=0 16a+4b+c=0 c=-2 解得a=1/2,b=-3/2,c=-2 ∴解析式為y=1/2x²;-3/2x-2 ∵AC²;+BC²;=AB²;, ∴△ABC是RT△. 有疑問,請追問;若滿意,請採納,謝謝!
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