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(1)將兩個點的座標代入,得 log2(a-1)-b=0 log2(a+1)-b=1 相减,得 log2[(a+1)/(a-1)]=1 所以(a+1)/(a-1)=2 解得a=3,代入求得b=1 所以f(x)=log2(x+3)-1 (2)令f(x)
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