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B非空,說明x^2-2ax+b=0有解B包含於A,說明A的值是B的解(1)B有兩個元素將-1,1代入x^2-2ax+b=0得(-1)^2-2a*(-1)+b=0(1)^2-2a*(1)+b=0 a=0 b=-1(2)B只有一個元素4*a^2-4*b=0即b=a^2將1代入得1-2a+a^2=0即a=1,b=1…
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