Contact us
Choose a category below so we can get back to you as quickly as possible.
由集合A中的不等式變形得:(x-1)(x-4)>0,解得:x>4或x<1,即A=(-∞,1)∪(4,+∞);令f(x)=x2-2ax+a+2,由A∩B≠∅,得f(x)與x軸無交點或兩交點在區間[1,4]之間,∴△=4a2-4(a+2)<0或△=4a2−4…
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.