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不妨設D,E,F分別在邊AB,BC,AC上.∵△ABC,△DEF為正三角形,∴∠A=∠B=∠C=60∠EDF=∠FED=∠EFD=60∠,DE=DF=EF∴∠BDE+∠ADF=180-60=120∠ADF+∠AFD=180-60=120∴∠AFD=∠BDE∴△ADF≌△BED同理△BED≌△CFE∴AD=BE= CF…
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