sin^22θ+2cos^2θcos2θ=2cos^2θ

sin^22θ+2cos^2θcos2θ=2cos^2θ

sin²;2θ+2cos²;θcos2θ
=(2sinθcosθ)²;+2cos²;θ(1-2sin²;θ)
=4sin²;θcos²;θ+2cos²;θ-4sin²;θcos²;θ
=2cos²;θ