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當x=0時, f(-0)= -f(0) f(0)= - f(0) f(0)=0 當x0 f(-x)= -(-x)^2+2x+2 = - x^2+2x+2 因為f(x)是奇函數,所以,f(-x)= - f(x) -f(x)= - x^2+2x+2 f(x)=x^2-2x-2 ` {x^2-2x-2(x0)
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