方程y=sin(x+y)所的隱函數的導數

方程y=sin(x+y)所的隱函數的導數

兩邊對x求導:
y'=cos(X+y)×(1+y')=cos(x+y)+y'cos(x+y)
{1-cos(x+y)}y'=cos(x+y)
y'=cos(x+y)/{1-cos(x+y)}