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已知f(x)是定義在R上的奇函數,當x≥0時,f(x)=x²;-2x, 令x0 f(-x)=x^2+2x 奇函數f(-x)=-f(x)所以 -f(x)=x^2+2x 則f(x)=-x^2-2x 所以 f(x)=x²;-2x(x>=0) =-x^2-2x(x
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