P1(2,-1),P2(0,5),且P在P1P2的延長線上,使|p1p|=2|p ;p2|,則點P為() A.(2,11)B.(34,3)C.(23,3)D.(2,-7)

P1(2,-1),P2(0,5),且P在P1P2的延長線上,使|p1p|=2|p ;p2|,則點P為() A.(2,11)B.(34,3)C.(23,3)D.(2,-7)

由題意知P1P2=P2P,設P(x,y),則(-2,6)=(x,y-5),∴x=-2y-5=6,∴x=-2y=11,∴點P的座標為(-2,11).故選A.