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先第一方程乘以2得到4x+6y=2m 再减去第二個方程就得到y=2m-n 再代回原來的第一個方程得到2x+3(2m-n)=m 從而解得x=(3n-5m)/2 原方程組的解是:x=(3n-5m)/2,y=2m-n. 注:你的第二個方程打錯了,應該是4x+5y=n
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