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分析不妨先求0~1999的所有數位之和,再求2000~2009的所有數位之和. 解(1+9×3)×(2000÷2) =28×1000 =28000 2×10+1+2+…+9 =20+45 =65 28000+65 =28065 答所求數位之和為28065. 這樣!
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