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(1)假設a,b是正的自然數,則有a方+b方≥2ab,相等時候為2(a方+b方)≥40*40=1600,所以a方+b方的最小值為1600÷2=800 (2)ab的最大值是在a,b是正的自然數的情况下,a+b=40≥2√ab,所以最小值是20*20=400
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