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∵x,y均為正實數,且xy=x+y+3∴xy=x+y+3≥2xy+3 ; ;(當x=y時取等號)即(xy)2-2xy-3≥0∴(xy+1)(xy-3)≥0∵x,y均為正實數∴xy+1>0∴xy-3≥0 ;即xy≥9故xy的最小值為9.
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