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已知x^2+y^2=4,那麼:x²;=4-y²; 所以: x²;+2y=4-y²;+2y=5-(y²;-2y+1)=5-(y-1)²; 由題意可得:-2≤y≤2 所以當y=-2時,-(y-1)²;有最小值為-9,此時:x²;+2y的最小值為-4.
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