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設l交抛物線於A(x1,y1)、B(x2,y2)兩點,由y12=6x1、y22=6x2,得(y1-y2)(y1+y2)=6(x1-x2),又P(4,1)是A、B的中點,∴y1+y2=2,∴直線l的斜率k=y1−y2x1−x2=3,∴直線l的方程為3x-y-11=0.
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