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a、b、c∈[0,2] 所以a(b-2)(c-2)>=0 展開就是a(bc-2b-2c+4)>=0 4a+abc>=2ac+2bc 又b^2+c^2>=2bc 相加就是4a+b^2+c^2+abc≥2ab+2bc+2ca
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