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(a+b)²;=11,得:a²;+b²;+2ab=11(a-b)²;=5,得:a²;+b²;-2ab=5兩式相加,得:2(a²;+b²;)=16所以:a²;+b²;=8已知:(a+b)²;=11,(a-b)²;=5,則a²;+ b²;的值等於_8…
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