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x+y=m①5x+3y=13②,②-①×3得:2x=13-3m,即x=13−3m2,將x=13−3m2代入①得:y=5m+32,根據題意得:13−3m2≥05m+32≥0,解得:-35≤m≤133,則整數m=0,1,2,3,4.
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