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x+y=m,等式兩邊同時乘以3,得3x+3y=3m,此等式與等式 5x+3y=13 左邊減左邊,右邊減右邊得 2x=13-3m,所以x=(13-3m)/2,x的值帶入x+y=m,得y=(5m-13)/2,因為x,y均是非負整數,所以(13-3m)/2≥0,且(5m-13)/2≥0,從而推出13/5≤m≤13/3,因為m是整數,所以m=3或4.
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