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設點(x,y)與兩條直線3x+4y+5=0,4x-3y-7=0等距離,則由點到直線的距離公式,得 |3x+4y+5|/√(3^2+4^2)=|4x-3y-7|/√(4^2+3^2) 3x+4y+5=±(4x-3y-7) 所求的軌跡是兩條線: x-7y-12=0 7x+y-2=0
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