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動點P(x,y)到頂點F(1,0)的距離為(x-1)^2+y^2的開方 P(x,y)到定直線x=4的距離為|x-4| 距離之比為1:2 (x-1)^2+y^2的開方:|x-4|=1:2 2*(x-1)^2+y^2的開方=|x-4| 平方 4(x-1)^2+4*y^2=(x-4)^2 展開整理即可
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