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選C a/b>c/d則ad>bc,b/a+b-d/c+d把兩項通分母,化簡為 (bc+bd)/(a+b)*(c+d)-(da+bd)/(a+b)*(c+d)再化簡 (bc-ad)/(a+b)*(c+d) ∵bc<ad∴分子小於0,分母大於0 故選C
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