如圖,AB=AC,AD=AE,∠BAC=∠DAE.求證:△ABD≌△ACE.

如圖,AB=AC,AD=AE,∠BAC=∠DAE.求證:△ABD≌△ACE.

證明:∵∠BAC=∠DAE,∴∠BAC+∠CAD=∠DAE+∠CAD,即∠BAD=∠EAC,在△ABD和△ACE中AB=AC∠BAD=∠EACAE=AD,∴△ABD≌△ACE.