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sin(x^2-1)當x趨向於1等於0,是無窮小量,用等價無窮小量代換sinx——〉x,所以,sin(x^2-1)——〉(x^2-1),(x^2-1)/(x-1)=x+1,當x趨向於1時,x+1趨向於2,所以答案是2. 以上是極限的方法 當然,用洛必達法則也很好算~
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