Contact us
Choose a category below so we can get back to you as quickly as possible.
sinπx=-sin(πx-π)【利用三角函數公式】 於是 sinπx/(x^2-1) =-sin(πx-π)/(x^2-1) =-sin[π(x-1)]/[(x-1)(x+1)]【整體出來了吧】 =-π/2
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.