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令x-y=a,y-z=b,則x-z=a+b 1/a+2/b-n/(a+b)>=0 同乘ab(a+b) b(a+b)+2a(a+b)-nab>=0 b²;+2a²;+3ab-nab>=0 2(a-b/√2)²;+2√2ab+3ab-nab>=0 所以只要2√2ab+3ab-nab>=0 n
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