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設這條高為x,三角形的3邊為a,b,c.∴4a=12c=xb,解得a=3c,b=12cx,∵a-c<b,a+c>b,解得3<x<6,∵x為整數,∴x只能為4或5,∵是不等邊三角形,∴高不能為4,∴最長可能為5,故選B.
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