Contact us
Choose a category below so we can get back to you as quickly as possible.
由原方程,得(a+2)x+3=0,∵關於x的方程:ax+4=1-2x恰為一元一次方程,∴a+2≠0.解得,a≠-2.故答案是:a≠-2.
關於x的一元一次方程ax+b=0有無數解的條件是:a=b=0.故答案是:a=b=0.
We and our partners use cookies and other technologies to analyze traffic and optimize your experience. View more info and control your cookies settings at any time in our Cookies Policy.