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a(n)=2a(n-1)+1兩邊同加1a(n)+1 = 2a(n-1)+2a(n)+1=2 [ a(n-1)+1 ]設b(n)=a(n)+1b(n)=2b(n-1)所以b(n)為公比為2的等比數列b1=a1+1=b(n)=b(1)*2^n-1即a(n)= [ a(1)+ 1] * 2^(n-1)- 1
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