In space quadrilateral ABCD, e, F, G and H are the midpoint of AB, BC, CD and Da respectively. If AC is perpendicular to BC, it is proved that efgh is a rectangle

In space quadrilateral ABCD, e, F, G and H are the midpoint of AB, BC, CD and Da respectively. If AC is perpendicular to BC, it is proved that efgh is a rectangle

Because EF and GH are the median lines of △ ABC and △ ACD respectively
So EF / / = GH = AC / 2
So efgh is a parallelogram
Because EF / / AC and AC ⊥ BC
So EF ⊥ EH
So efgh is a rectangle