Given AB = 2BC of rectangle ABCD, take point E on CD to make AE = EB, then the angle EBC is equal to A 60 B 45 C 30 D 15

Given AB = 2BC of rectangle ABCD, take point E on CD to make AE = EB, then the angle EBC is equal to A 60 B 45 C 30 D 15

45°
If AE = EB, then e must be on the vertical bisector of AB, and because point E is on CD, so point e must be at the midpoint of CD, that is to say, EC = DC = CD / 2, so CE = CB, so triangle ECB is isosceles right angle, so angle EBC = 45 °