In square ABCD, P is a point on diagonal AC, PE ⊥ AB is in E, PF ⊥ BC is in F. try to guess the quantity and position relationship between EF and PD, and give the proof We need to prove the process in detail

In square ABCD, P is a point on diagonal AC, PE ⊥ AB is in E, PF ⊥ BC is in F. try to guess the quantity and position relationship between EF and PD, and give the proof We need to prove the process in detail

PD=EF
∵PE⊥AB,PF⊥BC,AB⊥BC
∴∠PEB=∠PFB=∠B=90°
The quadrilateral pebf is a rectangle
Link PB
∵ in △ PCD and △ PCB
PC=PC,∠PCD=∠PCB=45°,PD=PB
∴△PCD≌△PCB
PD=PB
In rectangular pebf, Pb = EF
∴PD=EF