As shown in the figure, in the trapezoidal ABCD, AD / / BC, ∠ ABC = 60 °. ∠ DCB = 30 ° AB = 4, find BC ad
In the right triangle ABM and DCN, ab = 4. Sin60 = am / AB, then BM! And NC with tan30
In the right triangle ABM and DCN, ab = 4. Sin60 = am / AB, then BM! And NC with tan30