如圖,在梯形abcd中,ad//bc,∠abc=60°.∠dcb=30°,ab=4,求bc-ad.

如圖,在梯形abcd中,ad//bc,∠abc=60°.∠dcb=30°,ab=4,求bc-ad.

過ad作am、dn垂直bc,在直角三角形abm和dcn中!ab=4.sin60=am/ab求出am再求bm!用tan30求出nc