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證明:作BF⊥DC的延長線於F ∵ABCD是直角梯形,AB//CD,AD⊥DC ∴ABFD是矩形, ∴AD=BF, ∠BCF=∠ABE 又∵∠AEB=∠BFC=90°, ∠ABE=∠BCF,AB=BC ∴△AEB≌△BFC(角角邊) ∴AE=BF=AD
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