As shown in the figure, the square ABCD and an isosceles right triangle EFG (EF = EG) are placed on the same straight line. Now the triangle does not move, and the square moves to the right at a speed of 2 cm / s along the straight line at a constant speed? (1) At 10 seconds______ (2) in the 11th second______ (3) at the 13th second______ Square centimeter; 4______ Second, the area of the overlap is 18 square centimeters______ Second, the area of the overlap is 34 square centimeters

As shown in the figure, the square ABCD and an isosceles right triangle EFG (EF = EG) are placed on the same straight line. Now the triangle does not move, and the square moves to the right at a speed of 2 cm / s along the straight line at a constant speed? (1) At 10 seconds______ (2) in the 11th second______ (3) at the 13th second______ Square centimeter; 4______ Second, the area of the overlap is 18 square centimeters______ Second, the area of the overlap is 34 square centimeters

(1) (10 × 2-16) × (10 × 2-16) / - 2, = (20-16) × (20-16) / - 2, = 4 × 4 / 2, = 8 (square centimeter); answer: in the 10th second, 8 square centimeter. (2) (11 × 2-16) × (11 × 2-16) / - 2, = (22-16) × (22-16) / - 2, = 6 × 6 / 2, = 18 (square centimeter); answer: in the 11th second, 18 square centimeter. (3) 6 × 6 - [6 - (13 × 2-6-16)] × [(6-13 × 2-6-16)] / - 2 , = 6 × 6 - [6 - (26-6-16)] × [6 - (26-6-16)] / 2, = 6 × 6 - [6-4] × [6-4] / 2, = 6 × 6-2 × 2 / 2, = 36-2, = 34 (square centimeter). A: in the 13th second, 34 square centimeter. (4) because in the 11th second, the overlapping area is 18 square centimeter, so when the square moves to the other side of the triangle, point C and point G coincide, the overlapping area is also 18 square centimeter, (20 + 16) / 2, = 36 / 2= (5) because in the 13th second, the overlap area is 34 square centimeters, so when the square moves to the midpoint of the bottom of the triangle and coincides with point B of the square, the overlap area is 34 square centimeters, (6 + 16 + 20 △ 2) △ 2, = (6 + 16 + 10) △ 2, = 32 △ 2 = 16 (seconds), a: in the 13th and 16th seconds, the overlap area is 34 square centimeters So the answer is: 8, 18, 34, 11 and 18, 13 and 16