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y=(3cosx+1)/(sinx+2) ysinx+2y=3cosx+1 ysinx-3cosx=1-2y √(y^2+9)sin(x+φ)=1-2y Then - 1 ≤ (1-2y) / √ (y ^ 2 + 9) ≤ 1 The solution of inequality is y ∈ [- 2 / 3,2]
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