The range of function y = (2 + SiNx) / (3cosx-1) is

The range of function y = (2 + SiNx) / (3cosx-1) is

From y = (2 + SiNx) / (3cosx-1), we can get 3ycosx - SiNx = y + 2
√(1+9y^2)sin(c-x)=y+2,tanc=3y,
So | y + 2 | = √ (1 + 9y ^ 2) | sin (C-X) | ≤√ (1 + 9y ^ 2), the square of both sides can get y ^ 2 + 4Y + 4 ≤ 1 + 9y ^ 2, that is, 0 ≤ 8y ^ 2 - 4y-3, the solution is y ≤ (1 - √ 7) / 4, or Y ≥ (1 + √ 7) / 4. So the range of function y is (- ∞), (1 - √ 7) / 4) ∪ ((1 + √ 7) / 4, + ∞)

Elden Ring Premiere

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