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y=ln√(1+e^-2x) =1/2 ln(1+e^-2x) y''=1/2 [ln(1+e^-2x)]' =1/2 * 1/(1+e^-2x) *(1+e^-2x)' =1/[2(1+e^-2x)] *-2e^-2x =-2e^-2x / [2(1+e^-2x)] =-1/(e^2x+1)
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