Derivation of F (x) = x ^ 2x

Derivation of F (x) = x ^ 2x

y=f(x)=x^2x
lny=2xlnx
Derivation of X
(1/y)*y'=2*lnx+2x*1/x=2lnx+2
So y '= y * (2lnx + 2)
So f '(x) = x ^ 2x (2lnx + 2)